- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
easy
Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is........$times$
A
$8$
B
$4$
C
$2$
D
$32$
Solution
(c) Volume of $8$ small drops $=$ Volume of big drop
$8 \times \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {R^3}$ $==>$ $ R = 2r$
As capacity is $r$, hence capacity becomes $2$ times.
Standard 12
Physics
Similar Questions
medium