Electric potential in a region is varying according to the relation $V=\frac{3 x^2}{2}-\frac{y^2}{4}$, where $x$ and $y$ are in metre and $V$ is in volt. Electric field intensity (in $N/C$) at a point $(1 \,m , 2 \,m$ ) is ......
$3 \hat{i}-\hat{j}$
$-3 \hat{i}+\hat{j}$
$6 \hat{i}-2 \hat{j}$
$-6 \hat{i}+2 \hat{j}$
The electric potential at a point in free space due to charge $Q$ coulomb is $V=Q$$ \times {10^{11}}\,V$ . The electric field at that point is
Figure shows three points $A$, $B$ and $C$ in a region of uniform electric field $\overrightarrow E $. The line $AB$ is perpendicular and $BC$ is parallel to the field lines. Then which of the following holds good. Where ${V_A} > {V_B}$ and ${V_C}$ represent the electric potential at points $A$, $B$ and $C$ respectively
Determine the electric field strength vector if the potential of this field depends on $x, y$ coordinates as $V=10$ axy
The electric potential varies in space according to the relation $V = 3x + 4y$. A particle of mass $0.1\,\, kg$ starts from rest from point $(2, 3·2)$ under the influence of this field. The charge on the particle is $+1\,\, μC$. Assume $V$ and $(x, y)$ are in $S.I.$ $units$ . The time taken to cross the $x-$ axis is.....$s$
Variation of electrostatic potential along $x$-direction is shown in the graph. The correct statement about electric field is