8. Introduction to Trigonometry
easy

કિંમત શોધો :

$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$

A

$-1$

B

$0$

C

$2.5$

D

$1$

Solution

$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}=\frac{\tan \left(90^{\circ}-64^{\circ}\right)}{\cot 64^{\circ}}$

$=\frac{\cot 64^{\circ}}{\cot 64^{\circ}}=1$

Standard 10
Mathematics

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