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8. Introduction to Trigonometry
easy
કિંમત શોધો :
$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$
A
$-1$
B
$0$
C
$2.5$
D
$1$
Solution
$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}=\frac{\tan \left(90^{\circ}-64^{\circ}\right)}{\cot 64^{\circ}}$
$=\frac{\cot 64^{\circ}}{\cot 64^{\circ}}=1$
Standard 10
Mathematics