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$(2 x-3)(2 x+5)$
$=(2 x)^{2}+(-3+5)(2 x)+(-3)(5)$
$=4 x^{2}+4 x-15$
From the following polynomials find out which of them has $(x+1)$ as a factor
$6 x^{3}+11 x^{2}-5 x-12$
Find $p(1), p(2)$ and $p(4)$ for each of the following polynomials
$p(t)=t^{2}-6 t+8$
Without actually calculating the cubes, find the value of each of the following
$(14)^{3}+(27)^{3}-(41)^{3}$
If $x=2 y+6,$ then what is the value of $x^{3}-8 y^{3}-36 x y-216 ?$
Write whether the statement are True or False. Justify your answer.
Zero of a polynomial is always $0.$
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