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2. Electric Potential and Capacitance
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Figure shows a positively charged infinite wire. $A$ particle of charge $2C$ moves from point $A$ to $B$ with constant speed. (Given linear charge density on wire is $\lambda = 4 \pi \varepsilon_0$)

A
work done by external agent $= 4\, ln2$
B
work done by electric force $= -2\, ln\, 2$
C
work done by electric force $= 4\, ln \,2$
D
$V_A-V_B = 2\, ln\, 2$
Solution

$\mathrm{E}=\frac{2 \mathrm{K} \lambda}{\mathrm{r}} \quad ; \mathrm{V}=-\int_{\infty}^{\mathrm{r}} \overrightarrow{\mathrm{E}} \cdot \mathrm{dr}$
${{\rm{V}}_{\rm{B}}} – {{\rm{V}}_{\rm{A}}} = – \int_2^1 {\overrightarrow {\rm{E}} } \cdot \overrightarrow {{\rm{dr}}} = – \left. {2{\rm{k}}\lambda \cdot \ell nr} \right|_2^1 = 2{\rm{k}}\lambda \cdot \ell n2$
Standard 12
Physics
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