Figure shows the electric lines of force emerging from a charged body. If the electric field at $A$ and $B$ are ${E_A}$ and ${E_B}$ respectively and if the displacement between $A$ and $B$ is $r$ then
${E_A} > {E_B}$
${E_A} < {E_B}$
${E_A} = \frac{{{E_B}}}{r}$
${E_A} = \frac{{{E_B}}}{{{r^2}}}$
The black shapes in the figure below are closed surfaces. The electric field lines are in red. For which case, the net flux through the surfaces is non-zero?
A charge of $1$ coulomb is located at the centre of a sphere of radius $10 \,cm$ and a cube of side $20 \,cm$. The ratio of outgoing flux from the sphere and cube will be
For a given surface the Gauss's law is stated as $\oint {E \cdot ds} = 0$. From this we can conclude that
What is the direction of electric field intensity ?
A long cylindrical shell carries positive surface charge $\sigma$ in the upper half and negative surface charge $-\sigma$ in the lower half. The electric field lines around the cylinder will look like figure given in : (figures are schematic and not drawn to scale)