Figure shows variation of electric field intensity E versus distance x . potential difference betwee

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2. Electric Potential and Capacitance

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Figure shows the variation of electric field intensity $E$ versus distance $x$. What is the potential difference between the points at $x=2 \,m$ and at $x=6 \,m$ from $O$ is ............. $V$

A

$30$

B

$60$

C

$40$

D

$80$

Solution

(a)

$V_2-V_6=-\int E d r$

$V_2-V_6=(10)(2)+\frac{1}{2}(10)(2)=30$

Standard 12

Physics

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