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2. Electric Potential and Capacitance
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Figure shows three circular arcs, each of radius $R$ and total charge as indicated. The net electric potential at the centre of curvature is
A
$\frac{Q}{{4\pi { \in _0}R}}$
B
$\frac{Q}{{2\pi { \in _0}R}}$
C
$\frac{2Q}{{\pi { \in _0}R}}$
D
$\frac{Q}{{\pi { \in _0}R}}$
Solution
$\mathrm{V}_{\mathrm{net}}$ at center
${\mathrm{V}_{\mathrm{net}}=\frac{\mathrm{K}(3 \theta+\theta-2 \theta)}{\mathrm{r}}} $
${\mathrm{V}_{\mathrm{net}}=\frac{2 \theta}{4 \pi \varepsilon_{0} \mathrm{r}}=\frac{\theta}{2 \pi \varepsilon_{0} \mathrm{r}}}$
Standard 12
Physics
