3 and 4 .Determinants and Matrices
medium

$x$ तथा $y$ ज्ञात कीजिए यदि $2\left[\begin{array}{ll}1 & 3 \\ 0 & x\end{array}\right]+\left[\begin{array}{ll}y & 0 \\ 1 & 2\end{array}\right]=\left[\begin{array}{ll}5 & 6 \\ 1 & 8\end{array}\right]$

A

$x=3$ तथा $y=3$

B

$x=3$ तथा $y=3$

C

$x=3$ तथा $y=3$

D

$x=3$ तथा $y=3$

Solution

$2\left[\begin{array}{ll}1 & 3 \\ 0 & x\end{array}\right]+\left[\begin{array}{ll}y & 0 \\ 1 & 2\end{array}\right]=\left[\begin{array}{ll}5 & 6 \\ 1 & 8\end{array}\right]$

$\Rightarrow\left[\begin{array}{ll}2 & 6 \\ 0 & 2 x\end{array}\right]+\left[\begin{array}{ll}y & 0 \\ 1 & 2\end{array}\right]=\left[\begin{array}{ll}5 & 6 \\ 1 & 8\end{array}\right]$

$\Rightarrow\left[\begin{array}{cc}2+y & 6 \\ 1 & 2 x+2\end{array}\right]=\left[\begin{array}{cc}5 & 6 \\ 1 & 8\end{array}\right]$

Comparing the corresponding elements of these two matrices, we have :

$2+y=5 \Rightarrow y=3$

$2 x+2=8 \Rightarrow x=3$

$\therefore x=3$ and $y=3$

Standard 12
Mathematics

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