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2. Polynomials
easy
Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(t)=2+t+2 t^{2}-t^{3}$
Option A
Option B
Option C
Option D
Solution
$p ( t )=2+ t +2 t ^{2}- t ^{3}$
$\because $ $p ( t )=2+ t +2 t ^{2}- t ^{3}=2+ t +2( t )^{2}-( t )^{3}$
$\therefore$ $p (0)=2+(0)+2(0)^{2}-(0)^{3}=2+0+0-0=2$
$p (1)=2+(1)+2(1)^{2}-(1)^{3}=2+1+2-1=4$
$p (2)=2+2+2(2)^{2}-(2)^{3}=2+2+8-8=4$
Standard 9
Mathematics
