8. Sequences and Series
easy

Find the $20^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=\frac{n(n-2)}{n+3}$ 

A

$\frac{360}{23}$

B

$\frac{360}{23}$

C

$\frac{360}{23}$

D

$\frac{360}{23}$

Solution

Substituting $n=20,$ we obtain

$a_{20}=\frac{20(20-2)}{20+3}=\frac{20(18)}{23}=\frac{360}{23}$

Standard 11
Mathematics

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