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8. Sequences and Series
easy
If the sum of the series $2 + 5 + 8 + 11............$ is $60100$, then the number of terms are
A
$100$
B
$200$
C
$150$
D
$250$
Solution
(b) Series, $2 + 5 + 8 + 11…………$
$a=2,d=3$ and let number of terms is $n$
then sum of $A.P.$ ${a_1} + {a_5} + {a_{10}} + {a_{15}} + {a_{20}} + {a_{24}} = 225$
$ \Rightarrow $ $60100 = \frac{n}{2}\left\{ {2 \times 2 + (n – 1)3} \right\}$
$ \Rightarrow $ $120200 = n(3n + 1)$
$ \Rightarrow $ $3{n^2} + n – 120200 = 0$
$ \Rightarrow $ $(n – 200)(3n + 601) = 0$
Hence $n = 200$.
Standard 11
Mathematics