8. Sequences and Series
easy

જેનું $n$ મું પદ આપેલ છે તે શ્રેણીનાં ${a_{20}}$પદ શોધો : $a_{n}=\frac{n(n-2)}{n+3}$  

A

$\frac{360}{23}$

B

$\frac{360}{23}$

C

$\frac{360}{23}$

D

$\frac{360}{23}$

Solution

Substituting $n=20,$ we obtain

$a_{20}=\frac{20(20-2)}{20+3}=\frac{20(18)}{23}=\frac{360}{23}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.