Find the mean and variance for the data 6,7,1 | vedclass

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Question

$6,7,10,12,13,4,8,12$

Mean,    $\bar x = \frac{{\sum\limits_{i = 1}^8 {{x_i}} }}{n}$

$=\frac{6+7+10+12+13+4+8+12}{8}=\frac{72}{8}

Vedclass · Accepted Answer

$9.25$

Vedclass · Answer

$6,7,10,12,13,4,8,12$

Mean,    $\bar x = \frac{{\sum\limits_{i = 1}^8 {{x_i}} }}{n}$

$=\frac{6+7+10+12+13+4+8+12}{8}=\frac{72}{8}=9$

The following table is obtained


	
		
			${x_i}$
			$\left( {{x_i} - \bar x} ight)$
			${\left( {{x_i} - \bar x} ight)^2}$
		
		
			$6$
			$-3$
			$9$
		
		
			$7$
			$-2$
			$4$
		
		
			$10$
			$-1$
			$1$
		
		
			$12$
			$3$
			$9$
		
		
			$13$
			$4$
			$16$
		
		
			$4$
			$-5$
			$25$
		
		
			$8$
			$-1$
			$1$
		
		
			$12$
			$3$
			$9$
		
		
			 
			 
			$74$
		
	


Variance  $\left( {{\sigma ^2}} ight) = \frac{1}{n}\sum\limits_{i = 1}^8 {{{\left( {{x_i} - \bar x} ight)}^2} = \frac{1}{8} 	imes 74}  = 9.25$

$\mathrm{x}$	$\mathrm{x}_{1}=2$	$\mathrm{x}_{2}=6$	$\mathrm{x}_{3}=8$	$\mathrm{x}_{4}=9$
$\mathrm{f}$	$4$	$4$	$\alpha$	$\beta$

Find the mean and variance for the data $6,7,10,12,13,4,8,12$

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${x_i}$	$\left( {{x_i} - \bar x} \right)$	${\left( {{x_i} - \bar x} \right)^2}$
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