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4. Linear Equations in Two Variables
easy
Find the points where the graph of the equation $3 x+4 y=12$ cuts the $x$ -axis and the $y$ -axis.
Option A
Option B
Option C
Option D
Solution
The graph of the linear equation $3 x+4 y=12$ cuts the $x$ -axis at the point where $y=0 .$ On putting $y=0$ in the linear equation, we have $3 x=12,$ which gives $x=4 .$ Thus, the required point is $(4,0).$
The graph of the linear equation $3 x+4 y=12$ cuts the $y$ -axis at the point where $x=0$. On putting $x=0$ in the given equation, we have $4 y=12,$ which gives $y=3 .$ Thus, the required point is $(0,3).$
Standard 9
Mathematics
