Find the probability that when a hand of $7$ cards is drawn from a well shuffled deck of $52$ cards, it contains atleast $3$ Kings.

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Total number of possible hands $=^{52} C _{7}$

$P ($ atleast $3$ King $)= P (3 $ Kings or $4$ Kings $) $

                                      $= P (3$ Kings $)+ P (4 $ Kings $)$

                                      $=\frac{9}{1547}+\frac{1}{7735}=\frac{46}{7735}$

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