Radius of circle in which a central angle of 60^{circ} intercepts an arc of length 37.4 ,cm ( use π

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3.Trigonometrical Ratios, Functions and Identities

easy

Find the radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $37.4 \,cm$ ( use $\pi=\frac{22}{7}$ ).

A

$35.7 \,cm$

B

$35.7 \,cm$

C

$35.7 \,cm$

D

$35.7 \,cm$

Solution

Here $l=37.4\, cm$ and $\theta=60^{\circ}=\frac{60 \pi}{180} radian =\frac{\pi}{3}$

Hence, by $r=\frac{l}{\theta},$ we have

$r=\frac{37.4 \times 3}{\pi}=\frac{37.4 \times 3 \times 7}{22}=35.7 \,cm$

Standard 11

Mathematics

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