Gujarati
Hindi
2. Electric Potential and Capacitance
hard

Find the ratio of energy stored in $5\,\mu F$ and $4\,\mu F$ capacitor in the given circuit in steady state

A

$0.6$

B

$0.7$

C

$0.8$

D

$0.9$

Solution

$I=\frac{2}{5+4} a m p \quad \Rightarrow \quad I=\frac{2}{9} A m p$

$V_{A C}=5 \times \frac{2}{9}$ volt $=\frac{10}{9}$ volt

$V_{D B}=4 \times \frac{2}{9}$ volt $=\frac{8}{9}$ volt

$\frac{U_{5 \mu F}}{U_{4 \mu F}}=\frac{\frac{1}{2} \times 5\left(\frac{8}{9}\right)^{2}}{\frac{1}{2} \times 4 \times\left(\frac{10}{9}\right)^{2}}=0.8$

Standard 12
Physics

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