Two capacitors of capacitances C and 2, C are | vedclass

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Question

$Q _{1}= CV \quad Q _{2}=2 C 	imes 2 V =4 CV$

$\Rightarrow$ By conservation of charge

$q_{i}=q_{f}$

$Q_{1}+Q_{2}=q_{1}+q_{2}$

$4 CV - CV

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

$Q _{1}= CV \quad Q _{2}=2 C 	imes 2 V =4 CV$

$\Rightarrow$ By conservation of charge

$q_{i}=q_{f}$

$Q_{1}+Q_{2}=q_{1}+q_{2}$

$4 CV - CV =( C +2 C ) V _{ C }$

$v _{ C }=\frac{3 CV }{3 C } \Rightarrow V$

$\Rightarrow \frac{1}{2} 	imes(3 C) 	imes V_{ c }^{2}$

$=\frac{1}{2} 	imes 3 C 	imes V ^{2}=\frac{3}{2} CV ^{2}$

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