Find the union of each of the following pairs of sets :
$A = \{ x:x$ is a natural number and multiple of $3\} $
$B = \{ x:x$ is a natural number less than $6\} $
$A = \{ x:x$ is a natural number and multiple of $3\} = \{ 3,6,9 \ldots \} $
As $B = \{ x:x$ is a natural number less than $6\} = \{ 1,2,3,4,5,6\} $
$\therefore A \cap B=\{3\}$
If $A = \{x : x$ is a multiple of $4\}$ and $B = \{x : x$ is a multiple of $6\}$ then $A \cap B$ consists of all multiples of
If $A, B$ and $C$ are three sets such that $A \cap B = A \cap C$ and $A \cup B = A \cup C$ then
If $A$ and $B$ are two sets, then $A \cup B = A \cap B$ iff
If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
If $A=\{1,2,3,4\}, B=\{3,4,5,6\}, C=\{5,6,7,8\}$ and $D=\{7,8,9,10\} ;$ find
$A \cup B$