Find the union of each of the following pairs of sets :
$A = \{ x:x$ is a natural number and multiple of $3\} $
$B = \{ x:x$ is a natural number less than $6\} $
$A = \{ x:x$ is a natural number and multiple of $3\} = \{ 3,6,9 \ldots \} $
As $B = \{ x:x$ is a natural number less than $6\} = \{ 1,2,3,4,5,6\} $
$\therefore A \cap B=\{3\}$
If $X$ and $Y$ are two sets such that $n( X )=17, n( Y )=23$ and $n( X \cup Y )=38$
find $n( X \cap Y )$
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$B-D$
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$D-A$
Consider the following relations :
$(1) \,\,\,A - B = A - (A \cap B)$
$(2) \,\,\,A = (A \cap B) \cup (A - B)$
$(3) \,\,\,A - (B \cup C) = (A - B) \cup (A - C)$
which of these is/are correct
If $A$ and $B$ are sets, then $A \cap (B -A)$ is