Let A and B be two sets such that n(A) = 0.16,,n(B) = 0.14,,n(A cup B) = 0.25 . Then n(A cap B) is e

English

Gujarati

Hindi

1.Set Theory

easy

Let $A$ and $B$ be two sets such that $n(A) = 0.16,\,n(B) = 0.14,\,n(A \cup B) = 0.25$. Then $n(A \cap B)$ is equal to

A

$0.3$

B

$0.5$

C

$0.05$

D

None of these

Solution

(c) $n(A \cup B) = n(A) + n(B) – n(A \cap B)$

$0.25 = 0.16 + 0.14 – n(A \cap B)$

==> $n(A \cap B) = 0.30 – 0.25 = 0.05$.

Standard 11

Mathematics

Share

Similar Questions

Find the union of each of the following pairs of sets :

$A=\{1,2,3\}, B=\varnothing$

easy

If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find

$D-C$

easy

Let $A$ and $B$ be two sets. Then

easy

If $A, B$ and $C$ are non-empty sets, then $(A -B) \cup (B -A)$ equals

easy

If $A=\{x \in R:|x|<2\}$ and $B=\{x \in R:|x-2| \geq 3\}$ then

medium

(JEE MAIN-2020)