If ${N_a} = \{ an:n \in N\} ,$ then ${N_3} \cap {N_4} = $
If ${N_a} = \{ an:n \in N\} ,$ then ${N_3} \cap {N_4} = $
- A
${N_7}$
- B
${N_{12}}$
- C
${N_3}$
- D
${N_4}$
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