Find the zero of the polynomial : $p(x) = x + 5$
$0$
$-5$
$5$
$4$
We have $p(x) = x + 5 $ $\therefore $ $p(x) = 0$
$\Rightarrow$ $x + 5 = 0$ or $ x = – 5$
Thus, a zero of $x+5$ is $(-5)$.
Factorise each of the following : $27 p^{3}-\frac{1}{216}-\frac{9}{2} p^{2}+\frac{1}{4} p$
Factorise : $2 x^{2}+y^{2}+8 z^{2}-2 \sqrt{2} x y+4 \sqrt{2} y z-8 x z$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=x^{2}-1, \,x=1,\,-1$
Find the value of the polynomial $5x -4x^2+ 3$ at $x = -\,1$.
Evaluate the following products without multiplying directly : $103 \times 107$
Confusing about what to choose? Our team will schedule a demo shortly.
