Five point charges each having magnitude 'q' are placed at corners of regular hexagon as sho

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1. Electric Charges and Fields

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Five point charges each having magnitude $'q'$ are placed at the corners of regular hexagon as shown in figure. Net electric field at the centre $'O'$ is $\vec E$ . To get net electric field at $'O'$ to be $6\vec E$ , charge placed on the remaining sixth corner should be

A

$6\,q$

B

$-6\,q$

C

$5\,q$

D

$-5\,q$

Solution

$\overrightarrow{\mathrm{E}}_{0}=\frac{6 \mathrm{kq}}{\mathrm{a}^{2}}=6 \overrightarrow{\mathrm{E}}$

Standard 12

Physics

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