For a chemical reaction $A \to B$ it is found that the rate of reaction doubles, when the concentration of $A$ is increased four times. The order in $A$ for this reaction is
$2$
$1$
$0.5$
$0$
The possible mechanism for the reaction
$2NO + Br \to 2NOBr$ is
$NO + Br_2 \rightleftharpoons NOBr_2$ (Fast)
$NOBr_2 + NO \to 2NOBr$ (Slow)
The rate law expression is
The reaction, ${N_2}{O_5} \longrightarrow 2NO + \frac{1}{2}\,{O_2}$ is of first order for $N_2O_5$ with rate constant $6.2 \times 10^{-4}\, s^{-1}$. what is the value of rate of reaction when $[N_2O_5] = 1.25\, mol\, L^{-1}$
The order of a reaction which has the rate expression $\frac{{dc}}{{dt}} = K{[E]^{3/2}}{[D]^{3/2}}$ is
How can you determine the rate law of the following reaction ?
$2NO\,(g) + O_2\,(g)\to 2NO_{2} \,(g)$
The rate of reaction between $A$ and $B$ increases by a factor of $100,$ when the concentration of $A$ is increased $10$ folds. The order of reaction with respect to $A$ is