For adiabatic processes left( {gamma = frac{{{Cₚ}}}{{{Cᵥ}}}} right)

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11.Thermodynamics

easy

For adiabatic processes $\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)$

A

${P^\gamma }V$ = constant

B

${T^\gamma }V$= constant

C

$T{V^{\gamma - 1}}$ =constant

D

$T{V^\gamma }$ = constant

Solution

(c)In adiabatic process $P{V^\gamma } = $constant
==> $\left( {\frac{{RT}}{V}} \right).{V^\gamma } = $constant ==> $T{V^{\gamma – 1}}$= constant

Standard 11

Physics

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