For adiabatic processes $\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)$
${P^\gamma }V$ = constant
${T^\gamma }V$= constant
$T{V^{\gamma - 1}}$ =constant
$T{V^\gamma }$ = constant
A tyre filled with air $({27^o}C,$ and $2$ atm) bursts, then what is temperature of air ....... $^oC$ $(\gamma = 1.5)$
A thermodynamic cycle $xyzx$ is shown on a $V-T$ diagram.
The $P-V$ diagram that best describes this cycle is
(Diagrams are schematic and not to scale)
Given below are two statement
Statement $-I$ : What $\mu$ amount of an ideal gas undergoes adiabatic change from state $\left( P _{1}, V _{1}, T _{1}\right)$ to state $\left( P _{2}, V _{2}, T _{2}\right)$, the work done is $W =\frac{1 R \left( T _{2}- T _{1}\right)}{1-\gamma}$, where $\gamma=\frac{ C _{ P }}{ C _{ V }}$ and $R =$ universal gas constant,
Statement $-II$ : In the above case. when work is done on the gas. the temperature of the gas would rise.
Choose the correct answer from the options given below
One mole of an ideal gas expands adiabatically from an initial state $\left(T_A, V_0\right)$ to final state $\left(T_f, 5 V_0\right)$. Another mole of the same gas expands isothermally from a different initial state ( $T_{\mathrm{B}}, \mathrm{V}_0$ ) to the same final state $\left(T_{\mathrm{f}}, 5 V_0\right)$. The ratio of the specific heats at constant pressure and constant volume of this ideal gas is $\gamma$. What is the ratio $T_{\mathrm{A}} / T_{\mathrm{B}}$ ?
A sample of gas with $\gamma=1.5$ is taken through an adiabatic process in which the volume is compressed from $1200\, {cm}^{3}$ to $300\, {cm}^{3}$. If the initial pressure is $200\, {kPa}$. The absolute value of the workdone by the gas in the process $= \,..... J.$