If $A = \left( {\begin{array}{*{20}{c}}1&{ – 2}&1\\2&1&3\end{array}} \right)$ and $B = \left( {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right)$, then ${(AB)^T}$ is equal to

The matrix $\left[ {\begin{array}{*{20}{c}}0&5&{ – 7}\\{ – 5}&0&{11}\\7&{ – 11}&0\end{array}} \right]$is known as

Let $A\, = \,\left( {\begin{array}{*{20}{c}}
0&{2q}&r\\
p&q&{ – r}\\
p&{ – q}&r
\end{array}} \right)$. If $A{A^T}\, = \,{I_3},\,\left| p \right|$ then $\left| p \right|$ is

For $a $ matrix  $ A, AI = A $ and $A{A^T} = I$is true for

If $ A$  is a symmetric matrix and $n \in N$, then ${A^n}$ is