3 and 4 .Determinants and Matrices
normal

If $ A$  is a symmetric matrix and $n \in N$, then ${A^n}$ is

A

Symmetric

B

Skew symmetric

C

A Diagonal matrix

D

None of these

Solution

(a) Since $A$ is symmetric, therefore ${A^T} = A$.

Now ${({A^n})^T} = {({A^T})^n} = {(A)^n}$

$\therefore $ ${A^n}$ is also a symmetric matrix.

Standard 12
Mathematics

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