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3 and 4 .Determinants and Matrices
normal
If $ A$ is a symmetric matrix and $n \in N$, then ${A^n}$ is
A
Symmetric
B
Skew symmetric
C
A Diagonal matrix
D
None of these
Solution
(a) Since $A$ is symmetric, therefore ${A^T} = A$.
Now ${({A^n})^T} = {({A^T})^n} = {(A)^n}$
$\therefore $ ${A^n}$ is also a symmetric matrix.
Standard 12
Mathematics