11.Thermodynamics
easy

For the given cyclic process $CAB$ as shown for a gas, the work done is ..... $J$

A

$30$

B

$10$

C

$1$

D

$5$

(JEE MAIN-2019)

Solution

Work done $=$ Area of loop
                   $= \frac{1}{2} (4) (5)$
                   $= 10\, J$

Standard 11
Physics

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