3 and 4 .Determinants and Matrices
medium

For the system of linear equations :

$x-2 y=1, x-y+k z=-2, k y+4 z=6, k \in R$

consider the following statements :

$(A)$ The system has unique solution if $k \neq 2$, $k \neq-2$

$(B)$ The system has unique solution if $k =-2$.

$(C)$ The system has unique solution if $k =2$.

$(D)$ The system has no-solution if $k =2$.

$(E)$ The system has infinite number of solutions if $k \neq-2$

Which of the following statements are correct?

A

$(C)$ and $(D)$ only

B

$(B)$ and $(E)$ only

C

$(A)$ and $(E)$ only

D

$(A)$ and $(D)$ only

(JEE MAIN-2021)

Solution

$D =\left|\begin{array}{ccc}1 & -2 & 0 \\ 1 & -1 & k \\ 0 & k & 4\end{array}\right|=4- k ^{2}$

so, $A$ is correct and $B, C, E$ are incorrect. If $k =2$

$D_{1}=\left|\begin{array}{ccc}1 & -2 & 0 \\ -2 & -1 & 2 \\ 6 & 2 & 4\end{array}\right|=-48 \neq 0$

So no solution

$D$ is correct.

Standard 12
Mathematics

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