Force acts for 20,s on a body of mass 20,kg , starting from rest, after which force ceases and then

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4-1.Newton's Laws of Motion

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Force acts for $20\,s$ on a body of mass $20\,kg$, starting from rest, after which the force ceases and then body describes $50\,m$ in the next $10\,s$. The value of force will be $..........\,N$

A

$40$

B

$5$

C

$20$

D

$10$

(JEE MAIN-2023)

Solution

$50= V \times 10$

$V =5\,m / s$

$V =0+ a \times 20$

$5= a \times 20$

$a =\frac{1}{4}\,m / s ^2$

$F = ma =20 \times \frac{1}{4}=5\,N$

Standard 11

Physics

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