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4-1.Newton's Laws of Motion
medium
Four forces are acting at a point $P$ in equilibrium as shown in figure. The ratio of force $F_{1}$ to $F_{2}$ is $1: x$ where $x =....$
A$2$
B$1$
C$4$
D$3$
(JEE MAIN-2022)
Solution
$\theta=45^{\circ}$Taking components along $x\,\,and\,\,y$
$F _{1}=\sqrt{2}-\frac{1}{\sqrt{2}}=\frac{2-1}{\sqrt{2}}=\frac{1}{\sqrt{2}}$
$F _{2}=\sqrt{2}+\frac{1}{\sqrt{2}}=\frac{2+1}{\sqrt{2}}=\frac{3}{\sqrt{2}}$
$F _{1}: F _{2}=1: 3$
$x =3$
Standard 11
Physics
