Four particles A, B, C, D of mass frac{mathrm{m}}{2}, mathrm{~m}, 2 mathrm{~m}, 4 mathrm{~m} , have

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5.Work, Energy, Power and Collision

hard

Four particles $A, B, C, D$ of mass $\frac{\mathrm{m}}{2}, \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}$, have same momentum, respectively. The particle with maximum kinetic energy is:

A

$\mathrm{D}$

B

$\mathrm{C}$

C

$\mathrm{A}$

D

$B$

(JEE MAIN-2024)

Solution

$\mathrm{KE}=\frac{\mathrm{p}^2}{2 \mathrm{~m}}$

Same momentum, so less mass means more $\mathrm{KE}$.

So $\frac{\mathrm{m}}{2}$ will have $\max$. $\mathrm{KE}$.

Standard 11

Physics

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