Gujarati
5.Work, Energy, Power and Collision
easy

Four particles given, have same momentum which has maximum kinetic energy

A

Proton

B

Electron

C

Deutron

D

$\alpha $-particles

Solution

(b)$E = \frac{{{P^2}}}{{2m}}$

   $E \propto \frac{1}{m}$ (If $P =$ constant)
i.e. the lightest particle will possess maximum kinetic energy and in the given option mass of electron is minimum.

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.