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5.Work, Energy, Power and Collision
easy
Four particles given, have same momentum which has maximum kinetic energy
A
Proton
B
Electron
C
Deutron
D
$\alpha $-particles
Solution
(b)$E = \frac{{{P^2}}}{{2m}}$
$E \propto \frac{1}{m}$ (If $P =$ constant)
i.e. the lightest particle will possess maximum kinetic energy and in the given option mass of electron is minimum.
Standard 11
Physics
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