Two solids $A$ and $B$ of mass $1\, kg$ and $2\, kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies $(K.E.)_{ A }:( K.E. )_{ B }$ will be $\frac{ A }{1},$ so the value of $A$ will be ..... .

For a particle moving under the action of a variable force, kinetic energy-position graph is given, then

A body of mass $8\,kg$ and another of mass $2\, kg$ are moving with equal kinetic energy. The ratio of their respective momenta will be.

In the figure shown all the surfaces are frictionless, and mass of the block, $m = 1\, kg$. The block and wedge are held initially at rest. Now wedge is given a horizontal acceleration of $10\, m/s^2$ by applying a force on the wedge, so that the block does not slip on the wedge. Then work done by the normal force in ground frame on the block in $\sqrt 3 $ seconds is ......... $J$

If work is positive, then kinetic energy increases or decreases ?

A block moving horizontally on a smooth surface with a speed of $40\, {m} / {s}$ splits into two parts with masses in the ratio of $1: 2$. If the smaller part moves at $60\, {m} / {s}$ in the same direction, then the fractional change in kinetic energy is :-