Two solids A and B of mass 1, kg and 2, kg respectively are moving with equal linear momentum. ratio

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5.Work, Energy, Power and Collision

medium

Two solids $A$ and $B$ of mass $1\, kg$ and $2\, kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies $(K.E.)_{ A }:( K.E. )_{ B }$ will be $\frac{ A }{1},$ so the value of $A$ will be ..... .

A

$1$

B

$2$

C

$3$

D

$4$

(JEE MAIN-2021)

Solution

Kinetic energy $K =\frac{ P ^{2}}{2 m },\left( P _{ A }= P _{ B }\right)$

$K \propto \frac{1}{ m }$

$\frac{ K _{ A }}{ K _{ B }}=\frac{ m _{ B }}{ m _{ A }}$

$=\frac{2}{1}$

Standard 11

Physics

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