Four point masses are fastened to corners of a frame of negligible mass lying in xy plane. Let w be

English

Gujarati

Hindi

6.System of Particles and Rotational Motion

hard

Four point masses are fastened to the corners of $a$ frame of negligible mass lying in the $xy$ plane. Let $w$ be the angular speed of rotation. Then

A

rotational kinetic energy associated with a given angular speed depends on the axis of rotation.

B

rotational kinetic energy about y-axis is independent of m and its value is $Ma^2\omega^2.$

C

rotational kinetic energy about z-axis depends on m and its value is $(Ma^2 + mb^2)\omega^2$.

D

All of the above

Solution

Solution is Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.

Standard 11

Physics

Share

Similar Questions

A spherical solid ball of $10\,kg$ mass and radius $3\,cm$ is rotating about an axis passing through its centre with an angular velocity of $50\,radian/s$ the kinetic energy of rotation is ……. $J.$

medium

To maintain a rotor at a uniform angular speed of $200 \;rad s^{-1}$, an engine needs to transmit a torque of $180 \;N m .$ What is the power required by the engine?

(Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the engine is $100 \%$ efficient.

easy

If the rotational kinetic energy of a body is increased by $300\ \%$ then the percentage increase in its angular momentum will be ………. $\%$

medium

Two identical circular loops are moving with same kinetic energy one rolls $\&$ other slides. The ratio of their speed is

hard

A solid sphere is in rolling motion. In rolling motion a body possesses translational kinetic energy $(K_t)$ as well as rotational kinetic energy $(K_r)$ simultaneously. The ratio $K_t : (K_t + K_r)$ for the sphere is

medium

(NEET-2018)