To maintain a rotor at a uniform angular speed of $200 \;rad s^{-1}$, an engine needs to transmit a torque of $180 \;N m .$ What is the power required by the engine?
(Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the engine is $100 \%$ efficient.
Angular speed of the rotor, $\omega=200 rad / s$
Torque required, $\tau=180 Nm$
The power of the rotor $(P)$ is related to torque and angular speed by the relation
$P=\tau \omega$
$=180 \times 200=36 \times 10^{3}$
$=36 kW$
Hence, the power required by the engine is $36 kW$
Explain work done by torque.
A smooth tube of certain mass closed at both ends is rotated in a gravity free space and released. The two balls shown in figure moves towards the ends of the tube and stay there. Then which statement is incorrect about this whole system
$A$ uniform rod of mass $m$ and length $l$ hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is :
If the rotational kinetic energy of a body is increased by $300\ \%$ then the percentage increase in its angular momentum will be .......... $\%$
A flywheel is in the form of solid circular disc of mass $72\,\, kg$ and radius of $0.5\,m$ and it takes $70\, r.p.m.$ , then the energy of revolution approximately is ....... $J.$