To maintain a rotor at a uniform angular speed of $200 \;rad s^{-1}$, an engine needs to transmit a torque of $180 \;N m .$ What is the power required by the engine?
(Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the engine is $100 \%$ efficient.
Angular speed of the rotor, $\omega=200 rad / s$
Torque required, $\tau=180 Nm$
The power of the rotor $(P)$ is related to torque and angular speed by the relation
$P=\tau \omega$
$=180 \times 200=36 \times 10^{3}$
$=36 kW$
Hence, the power required by the engine is $36 kW$
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