Gujarati
Hindi
6.System of Particles and Rotational Motion
medium

If the rotational kinetic energy of a body is increased by $300\ \%$ then the percentage increase in its angular momentum will be .......... $\%$

A

$600$

B

$150$

C

$100$

D

$1500$

Solution

Percentage increase in momentum $=\frac{L_{2}-L_{1}}{L_{1}} \times 100$

$L \propto \sqrt{E} \Rightarrow E_{1}=E$

and $E_{2}=E+\frac{300}{100} E$

$\Rightarrow E_{2}=4 E$

Increase in momentum $=\frac{\sqrt{E_{2}}-\sqrt{E_{1}}}{\sqrt{E_{1}}} \times 100$

$=\frac{\sqrt{4 E}-\sqrt{E}}{\sqrt{E}} \times 100=100 \%$

Standard 11
Physics

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