From a group of $10$ men and $5$ women, four member committees are to be formed each of which must contain at least one woman. Then the probability for these committees to have more women than men, is
From a group of $10$ men and $5$ women, four member committees are to be formed each of which must contain at least one woman. Then the probability for these committees to have more women than men, is
- [JEE MAIN 2017]
- A
$\frac{21}{220}$
- B
$\frac{3}{11}$
- C
$\frac{1}{11}$
- D
$\frac{2}{23}$
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