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6.System of Particles and Rotational Motion
medium
Given $V _{ CM }=2\; m / s , m =2\; kg , R =4\; m $
Find angular momentum of ring about origin if it is in pure rolling. $kgm ^{2} / s$

A
$32$
B
$24$
C
$16$
D
$8$
(AIIMS-2019)
Solution
The moment of inertia about centre of mass is,
$I_{C M}=M R^{2}$
The angular velocity of the wheel is,
$\omega=\frac{V_{C M}}{R}$
$\omega=\frac{2}{4}=0.5 rad / s$
The angular momentum of the ring about origin is,
$\vec{L}=I_{C M} \omega+m V_{C M} R$
$=2 \times 16 \times 0.5+2 \times 2 \times 4$
$=16+16$
$=32\; kg \cdot m ^{2} / s$
Standard 11
Physics