- Home
- Standard 11
- Chemistry
6-2.Equilibrium-II (Ionic Equilibrium)
medium
Given the two concentration of $HCN (K_a = 10^{-9})$ are $0.1\,M$ and $0.001\,M$ respectively. What will be the ratio of degree of dissociation ?
A
$1$
B
$0.1$
C
$0.003$
D
$0.01$
Solution
$\alpha=\sqrt{\frac{\mathrm{Ka}}{\mathrm{C}}}$
$\frac{\alpha_{1}}{\alpha_{2}}=\sqrt{\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}}$
$\frac{\alpha_{1}}{\alpha_{2}}=\sqrt{\frac{10^{-3}}{10}}=\sqrt{10^{-2}}=10^{-1}=\frac{1}{10}=0.1$
Standard 11
Chemistry
