Half life of B{i^{210}} is 5 days. If we start with 50,000 atoms of this isotope, number of atoms le

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13.Nuclei

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Half life of $B{i^{210}}$ is $5$ days. If we start with $50,000$ atoms of this isotope, the number of atoms left over after $10$ days is

A

$5000$

B

$25000$

C

$12500$

D

$20000$

Solution

(c) ${N_t} = {N_0}{\left( {\frac{1}{2}} \right)^{t/T}} = 50000{\left( {\frac{1}{2}} \right)^{10/5}} = 12500$

Standard 12

Physics

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