Half life of a radioactive element is 10, days . time during which quantity remains 1/10 of initial

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13.Nuclei

easy

Half life of a radioactive element is $10\, days$. The time during which quantity remains $1/10$ of initial mass will be .........$days$

A

$100$

B

$50$

C

$33 $

D

$16$

Solution

(c) After three half lives $(i.e., \,30 \,days)$

it remains ${\left( {\frac{1}{2}} \right)^3} = \frac{1}{8},$

so it will remain $\frac{1}{{10}}th$, approximately in $33\, days.$

Standard 12

Physics

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