10-1.Thermometry, Thermal Expansion and Calorimetry
medium

A copper block of mass $5.0\, kg$ is heated to a temperature of $500^{\circ} C$ and is placed on a large ice block. What is the maximum amount of ice (ઇન $kg$) that can melt? [Specific heat of copper: $0.39\, Jg ^{-1 \circ} C ^{-1}$ and latent heat of fusion of water : $335 \,J g ^{-1}$ ]

A

$1.5$

B

$5.8$

C

$2.9$

D

$3.8$

(JEE MAIN-2022)

Solution

Heat given by block to get $0\,^{\circ} C$ temperature

$\Delta Q _{1}=5 \times\left(0.39 \times 10^{3}\right) \times(500-0)$

$=975 \times 10^{3} J$

Heat absorbed by ice to melt $m$ mass

$\Delta Q _{2}= m \times\left(335 \times 10^{3}\right) J$

$\Delta Q _{1}=\Delta Q _{2}$

$m \times\left(335 \times 10^{3}\right)=975 \times 10^{3}$

$m =\frac{975}{335}=2.910\, kg$

Standard 11
Physics

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