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10-1.Thermometry, Thermal Expansion and Calorimetry
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A copper block of mass $5.0\, kg$ is heated to a temperature of $500^{\circ} C$ and is placed on a large ice block. What is the maximum amount of ice (ઇન $kg$) that can melt? [Specific heat of copper: $0.39\, Jg ^{-1 \circ} C ^{-1}$ and latent heat of fusion of water : $335 \,J g ^{-1}$ ]
A
$1.5$
B
$5.8$
C
$2.9$
D
$3.8$
(JEE MAIN-2022)
Solution
Heat given by block to get $0\,^{\circ} C$ temperature
$\Delta Q _{1}=5 \times\left(0.39 \times 10^{3}\right) \times(500-0)$
$=975 \times 10^{3} J$
Heat absorbed by ice to melt $m$ mass
$\Delta Q _{2}= m \times\left(335 \times 10^{3}\right) J$
$\Delta Q _{1}=\Delta Q _{2}$
$m \times\left(335 \times 10^{3}\right)=975 \times 10^{3}$
$m =\frac{975}{335}=2.910\, kg$
Standard 11
Physics