How many bonds (bond order) does B_2 have ? | vedclass

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Question

The $B _2$ molecule is known to be formed by the combination of two Boron atoms, where they are linked by a covalent bond.

The atomic number of bor

Vedclass · Accepted Answer

$1$

Vedclass · Answer

The $B _2$ molecule is known to be formed by the combination of two Boron atoms, where they are linked by a covalent bond.

The atomic number of boron is $5$ , for which the electronic configuration of boron can be given as: $1 s^2\, 2 s^2\, 2 p^1$

The molecular orbital diagram for $B _2$ molecule can be shown as:

From the diagram, we can know that the number of electrons in bonding molecular orbitals is $4$ whereas the number of electrons in antibonding molecular orbitals is $2.$

Hence, the bond order is calculated as:

Bond order $=\frac{1}{2}(4-2)$

$=1$

How many bonds (bond order) does $B_2$ have ?

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