The molecular orbital configuration of a diatomic molecule is
$\sigma \,\,1{s^2}\,\,{\sigma ^*}\,\,1{s^2}\,\sigma \,\,2{s^2}\,{\sigma ^*}\,2{s^2}\,\,\sigma \,2p_x^2\,\left\{ {{}_{\pi \,2p_z^2}^{\pi \,2p_y^2}} \right.$
Its bond order is
$3$
$2.5$
$2$
$1$
Explain energy level diagram for molecular orbital form by $1\mathrm{s}$ orbitals.
Oxygen molecule is paramagnetic because
${N_2}$ and ${O_2}$ are converted into monocations $N_2^ + $ and $O_2^ + $ respectively. Which is wrong
For $F_2$ and $OF$ molecules consider the following statements
$(a)$ Bond order for both is one
$(b)$ $OF$ is paramagnetic but $F_2$ is diamagnetic
$(c)$ $F_2$ is more likely to dissociate into atoms than $OF$
$(d)$ Both have greater number of electrons in $BMO$ than that in $ABMO$
Which of the following statements are true $(T)$ or false $(F)$ respectively
Which of the following molecular orbitals has maximum number of nodal planes ?