Molecular orbital configuration of a diatomic molecule is sigma ,,1{s^2},,{sigma ^*},,1{s^2},sigma ,

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4.Chemical Bonding and Molecular Structure

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The molecular orbital configuration of a diatomic molecule is

$\sigma \,\,1{s^2}\,\,{\sigma ^}\,\,1{s^2}\,\sigma \,\,2{s^2}\,{\sigma ^}\,2{s^2}\,\,\sigma \,2p_x^2\,\left\{ {{}_{\pi \,2p_z^2}^{\pi \,2p_y^2}} \right.$

Its bond order is

A

$3$

B

$2.5$

C

$2$

D

$1$

Solution

(a) $B.O.$ $ = \frac{{{N_b} – {N_a}}}{2} = \frac{{10 – 4}}{2} = 3$.

Standard 11

Chemistry

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