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6.Permutation and Combination
easy
How many words can be formed by taking $3$ consonants and $2$ vowels out of $5$ consonants and $4$ vowels
A
$^5{C_3} \times {\,^4}{C_2}$
B
$\frac{{^5{C_3} \times {\,^4}{C_2}}}{5}$
C
$^5{C_3} \times {\,^4}{C_3}$
D
${(^5}{C_3} \times {\,^4}{C_2})\,(5)\,!$
Solution
(d) The letters can be select in $^5{C_3}{ \times ^4}{C_2}$ ways.
Therefore the number of arrangements are ${(^5}{C_3}{ \times ^4}{C_2})\,\,5\;!$.
Standard 11
Mathematics
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