How would you explain the lower atomic radius of $Ga$ as compared to $Al$?
How would you explain the lower atomic radius of $Ga$ as compared to $Al$?
| Atomic radius (in $pm$) | |
| Aluminium | $143$ |
| Gallium | $135$ |
Although $Ga$ has one shell more than $A l$ its size is lesser than $A l$ . This is because of the poor shielding effect of the $3 d -$ electrons. The shielding effect of $d -$ electrons is very poor and the effective nuclear charge experienced by the valence electrons in gallium is much more than it is in the case of $Al$
Similar Questions
$Be$ and $Al$ exhibit many properties which are similar, but the two elements differ in :
$Be$ and $Al$ exhibit many properties which are similar, but the two elements differ in :
${H_3}B{O_3}\,\xrightarrow{{{T_1}}}X\,\xrightarrow{{{T_2}}}Y\,\xrightarrow{{\operatorname{Re} d\,\,\,hot}}{B_2}{O_3}$
if $T_1 < T_2$ then $X$ and $Y$ respectively are
${H_3}B{O_3}\,\xrightarrow{{{T_1}}}X\,\xrightarrow{{{T_2}}}Y\,\xrightarrow{{\operatorname{Re} d\,\,\,hot}}{B_2}{O_3}$
if $T_1 < T_2$ then $X$ and $Y$ respectively are
Draw structure of $Al_2Cl_6$ and give uses of $AlCl_3$.
Draw structure of $Al_2Cl_6$ and give uses of $AlCl_3$.
Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF $$_{3}$ is bubbled through. Give reasons.
Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF $$_{3}$ is bubbled through. Give reasons.
Identify the correct statement for $B _{2} H _{6}$ from those given below.
$(A)$ In $B _{2} H _{6}$, all $B - H$ bonds are equivalent.
$(B)$ In $B _{2} H _{6}$ there are four $3-$centre$-2-$electron bonds.
$(C)$ $B _{2} H _{6}$ is a Lewis acid.
$(D)$ $B _{2} H _{6}$ can be synthesized form both $BF _{3}$ and $NaBH _{4}$.
$(E)$ $B _{2} H _{6}$ is a planar molecule.
Choose the most appropriate answer from the options given below..... .
Identify the correct statement for $B _{2} H _{6}$ from those given below.
$(A)$ In $B _{2} H _{6}$, all $B - H$ bonds are equivalent.
$(B)$ In $B _{2} H _{6}$ there are four $3-$centre$-2-$electron bonds.
$(C)$ $B _{2} H _{6}$ is a Lewis acid.
$(D)$ $B _{2} H _{6}$ can be synthesized form both $BF _{3}$ and $NaBH _{4}$.
$(E)$ $B _{2} H _{6}$ is a planar molecule.
Choose the most appropriate answer from the options given below..... .
- [JEE MAIN 2022]