If alpha ,,beta ,,gamma ,,delta are the | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Given that, $\alpha<\beta<\gamma<\delta$ and

$\sin \alpha=\sin \beta=\sin \gamma=\sin \delta=\mathrm{k}$

Also $\alpha, \beta, \gamma, \

Vedclass · Accepted Answer

$2\sqrt {\left( {1 + k} \right)} $

Vedclass · Answer

Given that, $\alpha<\beta<\gamma<\delta$ and

$\sin \alpha=\sin \beta=\sin \gamma=\sin \delta=\mathrm{k}$

Also $\alpha, \beta, \gamma, \delta$ are smallest positive angles, satisfying above two conditions.

$	herefore $ we can take $\beta=\pi-\alpha, \gamma=2 \pi+\alpha, \delta=3 \pi-\alpha$

The given expression

$=4 \sin \frac{\alpha}{2}+3 \sin \left(\frac{\pi}{2}-\frac{\alpha}{2}ight)$

$+2 \sin \left(\pi+\frac{\alpha}{2}ight)+\sin \left(\frac{3 \pi}{2}-\frac{\alpha}{2}ight)$

$=4 \sin \frac{\alpha}{2}+3 \cos \frac{\alpha}{2}-2 \sin \frac{\alpha}{2}-\cos \frac{\alpha}{2}$

$=2\left(\sin \frac{\alpha}{2}+\cos \frac{\alpha}{2}ight)$

$ = 2\sqrt {\left\{ {{{\left( {\sin \frac{\alpha }{2} + \cos \frac{a}{2}} ight)}^2}} ight\}} $

$=2 \sqrt{(1+\sin \alpha)}=2 \sqrt{(1+\mathrm{k})}$

If $\alpha ,\,\beta ,\,\gamma ,\,\delta $ are the smallest positive angles in ascending order of magnitude which have their sines equal to the positive quantity $k$ , then the value of $4\sin \frac{\alpha }{2} + 3\sin \frac{\beta }{2} + 2\sin \frac{\gamma }{2} + \sin \frac{\delta }{2}$ is equal to

Similar Questions

The equation ${\sin ^4}x + {\cos ^4}x + \sin 2x + \alpha = 0$ is solvable for

The number of real solutions $x$ of the equation $\cos ^2(x \sin (2 x))+\frac{1}{1+x^2}=\cos ^2 x+\sec ^2 x$ is

For each positive real number $\lambda$. Let $A_\lambda$ be the set of all natural numbers $n$ such that $|\sin (\sqrt{n+1})-\sin (\sqrt{n})|<\lambda$. Let $A_\lambda^c$ be the complement of $A_\lambda$ in the set of all natural numbers. Then,

One root of the equation $\cos x - x + \frac{1}{2} = 0$ lies in the interval

The number of solutions that the equation $sin5\theta cos3\theta = sin9\theta cos7\theta $ has in $\left[ {0,\frac{\pi }{4}} \right]$ is