If tan theta + tan 2theta + sqrt 3 tan theta | vedclass

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Question

(c) Given relation is

$	an 	heta + 	an 2	heta + \sqrt 3 	an 	heta 	an 2	heta = \sqrt 3 $

==> $\,	an 	heta + 	an 2	heta = \sqrt 3

Vedclass · Accepted Answer

$	heta = (3n + 1)\pi /9,\,\forall n \in I$

Vedclass · Answer

(c) Given relation is

$	an 	heta + 	an 2	heta + \sqrt 3 	an 	heta 	an 2	heta = \sqrt 3 $

==> $\,	an 	heta + 	an 2	heta = \sqrt 3 (1 - 	an 	heta 	an 2	heta )$

==> $\frac{{	an 	heta + 	an 2	heta }}{{1 - 	an 	heta 	an 2	heta }}$= $\sqrt 3 $

==> $	an 3	heta = 	an (\pi /3)$

==> $3	heta = n\pi + \frac{\pi }{3}$

==> $	heta = (3n + 1)\frac{\pi }{9}$.

If $\tan \theta + \tan 2\theta + \sqrt 3 \tan \theta \tan 2\theta = \sqrt 3 ,$ then

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